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Q.

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11m away from the starting point. The drunkard will fall into the pit after

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a

21s

b

29s

c

31s

d

37s

answer is B.

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Detailed Solution

For last 5 steps no back ward motion∴time taken for last 5m = 5 secremaining distance =11–5 m =6mwith forward and backward motion such that 2m time = 8s∴ for 6 m, time = 6/2 x 8 = 24sectotal time = 24 + 5 = 29 sec
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