First slide

Position Path Length (Distance) And Displacement

Question

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11m away from the starting point. The drunkard will fall into the pit after

Moderate

A

21s
B

29s
C

31s
D

37s

Solution

For last 5 steps no back ward motion
$∴$ time taken for last 5m = 5 sec
remaining distance =11–5 m =6m
with forward and backward motion such that 2m time = 8s
$∴$ for 6 m, time = 6/2 x 8 = 24sec
total time = 24 + 5 = 29 sec

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