A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11m away from the starting point. The drunkard will fall into the pit after
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a
21s
b
29s
c
31s
d
37s
answer is B.
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Detailed Solution
For last 5 steps no back ward motion∴time taken for last 5m = 5 secremaining distance =11–5 m =6mwith forward and backward motion such that 2m time = 8s∴ for 6 m, time = 6/2 x 8 = 24sectotal time = 24 + 5 = 29 sec