First slide

Fluid dynamics

Question

Due to constant leakage of water from the tank shown in figure, water level is lowering with a speed of u. The hole area is A and the cross sectional area of the tank is 10A. What will be the range of water stream on the horizontal ground ? Given that u = 4cm/sec

Moderate

Solution

Velocity of efflux, $V = \frac{10 A \times u}{A} = \frac{40}{100} m / s = \frac{2}{5} m / s .$
$\begin{array}{l} ∴ \frac{1}{2} g t^{2} = h \Rightarrow t = \sqrt{\frac{2 h}{g}} \\ ∴ R = v t = \frac{2}{5} \sqrt{\frac{2 h}{g}} m \end{array}$

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