First slide

Magnetic field due to a current carrying circular ring

Question

Due to 10 A of current flowing in a circular coil of 10 cm radius, the magnetic field produced at its centre is $3 .14 \times 10^{- 3} Wb / m^{2}$ . The number of turns in the coil will be

Easy

A

5000
B

100
C

50
D

25

Solution

$\begin{array}{l} B = \frac{μ_{0}}{4 π} . \frac{2 πNi}{r} \\ \Rightarrow 3 .14 \times 10^{- 3} = \frac{10^{- 7} \times 2 \times 3 .14 \times N \times 10}{10 \times 10^{- 2}} \Rightarrow N = 50 \end{array}$

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