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Due to 10 A of current flowing in a circular coil of 10 cm radius, the magnetic field produced at its centre is $3 .14 \times 10^{- 3} Wb / m^{2}$ . The number of turns in the coil will be

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Correct option is C

B= μ04π . 2πNir⇒ 3.14 × 10−3 = 10−7 × 2 ×3.14 × N ×1010 × 10−2 ⇒ N=50

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Due to 10 A of current flowing in a circular coil of 10 cm radius, the magnetic field produced at its centre is 3.14 × 10−3 Wb/m2. The number of turns in the coil will be

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Due to 10 A of current flowing in a circular coil of 10 cm radius, the magnetic field produced at its centre is $3 .14 \times 10^{- 3} Wb / m^{2}$ . The number of turns in the coil will be