Questions
Due to the flow of current in a circular loop of radius R, the magnetic induction produced at the centre of the loop is B. The magnetic moment of the loop is ( = permeability constant)
detailed solution
Correct option is B
B = μ0i2R ⇒ i = B × 2Rμ0 Now, M=i × A=iπR2 = B × 2Rμ0 × πR2 = 2πBR3μ0Talk to our academic expert!
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A circular loop has a radius of 5 cm and it is carrying a current of 0.1 A. Its magnetic moment is
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