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Q.

Due to the flow of current in a circular loop of radius R, the magnetic induction produced at the centre of the loop is B. The magnetic moment of the loop is (μ0 = permeability constant)

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a

BR3/2πμ0

b

2πBR3/μ0

c

BR2/2πμ0

d

2πBR2/μ0

answer is B.

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Detailed Solution

B = μ0i2R ⇒ i = B × 2Rμ0 Now, M=i × A=iπR2 = B × 2Rμ0 × πR2 = 2πBR3μ0

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Due to the flow of current in a circular loop of radius R, the magnetic induction produced at the centre of the loop is B. The magnetic moment of the loop is (μ0 = permeability constant)