First slide

Work

Question

Due to a force of $(6 \hat{i} + 2 \hat{j}) N$ the displacement of a body is $(3 \hat{i} - \hat{j}) m$ , then the work done is ….(in J)

Easy

Solution

Work done $= \vec{F} . \vec{s}$
$= (6 \hat{i} + 2 \hat{j}) \cdot (3 \hat{i} - \hat{j}) = 6 \times 3 - 2 \times 1 = 18 - 2 = 16 J$

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