Due to some force F1 a body oscillates with period 4/5 sec and due to other force F2 oscillates with period 3/5 sec. If both forces act simultaneously, the new period will be

Under the influence of one force F1=mω12y and under the action of another force, F2=mω22y.Under the action of both the forces F=F1+F2⇒mω2y=mω12y+mω2y⇒ω12+ω22⇒2πT2=2πT12+2πT22⇒T=T12T22T12+T22=452352452+352=0.48sec