Questions
Due to some force F1 a body oscillates with period 4/5 sec and due to other force F2 oscillates with period 3/5 sec. If both forces act simultaneously, the new period will be
detailed solution
Correct option is C
Under the influence of one force F1=mω12y and under the action of another force, F2=mω22y.Under the action of both the forces F=F1+F2⇒mω2y=mω12y+mω2y⇒ω12+ω22⇒2πT2=2πT12+2πT22⇒T=T12T22T12+T22=452352452+352=0.48secTalk to our academic expert!
Similar Questions
An ideal spring with spring-constant K is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the spring is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
