During an experiment an ideal gas is found to obey an additional gas law VT = constant. The gas is initially at temperature T and pressureP. When it is heated to the temperature2T, the resulting pressure is
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a
2P
b
P/2
c
4P
d
P/4
answer is C.
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Detailed Solution
P1V1T1=P2V2T2;P1P2=T1T2⋅V2V1; Given V∝1T∵V2V1=T1T2 and P1P2=T1T2×T1T2