Questions
During an experiment an ideal gas is found to obey an additional law Vp2 = constant. The gas is initially at temperature T and volume V. When it expands to volume 2V, the resulting temperature is [UP CPMT 2012]
detailed solution
Correct option is C
pV = RT = constant⇒ p=RTV Vp2 = constant⇒ VRTV2= constant ⇒ R2T2V= constant ⇒ T2V= constant ⇒T2V=T22V⇒ T'2=2T2⇒T'=2TTalk to our academic expert!
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For one-mole ideal gas, a process follows the relation where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?
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