During an experiment an ideal gas is found to obey an additional law VP2 = constant. The gas is initially at temperature T and volume V, when it expands to volume 2V, the resulting temperature is
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a
T2
b
2T
c
2T
d
T2
answer is C.
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Detailed Solution
Pv=RT=constant. (i) Also VP2=constant. (ii) From eqn.(i) P=RTV from eqn.(ii) VRTV2=constant R2T2V=constant or T2V=constant ∴ T2V=T'22V or T'2 = 2T2 ∴ T'=2T