Questions  

During an experiment an ideal gas is found to obey an additional law VP2 = constant. The gas is initially at temperature T and volume V, when it expands to volume 2V, the resulting temperature is

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ctaimg
a
T2
b
2T
c
2T
d
T2
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detailed solution

Correct option is C

Pv=RT=constant.                 (i) Also                 VP2=constant.                       (ii) From eqn.(i)   P=RTV from eqn.(ii)   VRTV2=constant                             R2T2V=constant      or     T2V=constant ∴                          T2V=T'22V          or                 T'2 = 2T2 ∴                           T'=2T


ctaimg

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For one-mole ideal gas, a process follows the relation P=V2V2+V02P0, where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?

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