Questions
During an experiment an ideal gas is found to obey an additional law = constant. The gas is initially at temperature T and volume V. When it expands to a volume 2V, the temperature becomes
detailed solution
Correct option is D
PV = RT (ideal gas equation)---------(i)V2P = C(additional law)-----------(ii)Dividing V = CRT ⇒ V ∝1Tor T = 1V (combined law)When volume (V) is doubled, temperature is halved i.e., T' = T2Talk to our academic expert!
Similar Questions
For one-mole ideal gas, a process follows the relation where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?
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