During an experiment an ideal gas is found to obey an additional law VP2 = constant. The gas is initially at a temperature 'T' and volume'V'. When it expands to a volume 2V, the temperature becomes
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a
T
b
2T
c
2T
d
T2
answer is C.
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Detailed Solution
PV∝T,P1P2×V1V2=T1T2According to given data P2V= constant⇒P1P2=V2V112⇒T1T2=V2V112V1V2