Questions
During an experiment an ideal gas is found to obey an additional law VP2 = constant. The gas is initially at a temperature 'T' and volume
'V'. When it expands to a volume 2V, the temperature becomes
detailed solution
Correct option is C
PV∝T,P1P2×V1V2=T1T2According to given data P2V= constant⇒P1P2=V2V112⇒T1T2=V2V112V1V2Talk to our academic expert!
Similar Questions
For one-mole ideal gas, a process follows the relation where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?
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