Q.

During a projectile motion, if the maximum height equals the horizontal range, then the angle of projection with the horizontal is

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a

tan-1(1)

b

tan-1(2)

c

tan-1(3)

d

tan-1(4)

answer is D.

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Detailed Solution

We find that H=R or u2sin2⁡θ2g=u22sin⁡θcos⁡θgor  tan⁡θ=4 or θ=tan−1⁡(4)
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