First slide

Second law

Question

During the rocket propulsion, gases ejecting with velocity 1 km/s relative to rocket. The rate of fuel consumption is $\frac{m}{10} kg / s$ ,where m is the instantaneous mass of the rocket. If air resistance varies according to equation f - 0.15 mv, then terminal velocity of the rocket is :

Moderate

A

300 m/s
B

600 m/s
C

7.92km/s
D

11.2 km/s

Solution

At terminal velocity F_net = 0
$\begin{array}{l} v_{gas} \frac{dm}{dt} = mg + f \\ \Rightarrow 1000 (\frac{m}{10}) = 10 m + 0 .15 mv \Rightarrow v = 600 m / s \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App