Q.

E2μ0 has the dimensions (E= electric field, μ0 = permeability of free space)

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a

M2L3T−2A2

b

MLT−4

c

ML3T−2

d

M−1L2TA−2

answer is B.

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Detailed Solution

E2μ0=ε0E2ε0μ0= energy / volume (1/ speed of light )2⇒E2μ0= energy ( speed )2 volume ⇒E2μ0=ML2T−2L2T−2L3=MLT−4
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E2μ0 has the dimensions (E= electric field, μ0 = permeability of free space)