Each pulley in figure has radius r and moment of inertia I. The acceleration of the block is
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a
(M−m)gM+m+2Ir2
b
(M−m)gM+m−2Ir2
c
(M−m)gM+m+Ir2
d
(M−m)gM+m−Ir2
answer is A.
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Detailed Solution
T1−mg=ma .....(i)rT1−T2=Iα ......(ii)Mg−T3=Ma ......(iii)rT2−T3=Iα ......(iv)and a = RFrom Eqs. (ii) + (iv), we getT1−T3=2IaR2From Eqs. (i) and (iii), we get⇒a=(M−m)gM+m+2Ir2