Each pulley in the figure has radius r and moment of inertia I. The acceleration of the block is
(M−m)gM+m+2Ir2
(M−m)gM+m−2Ir2
(M−m)gM+m+Ir2
(M−m)gM+m−Ir2
T1−mg=ma……..(i)
rT2−T1=Iα.........(ii)Mg−T3=Ma.........(iii)rT3−T2=Iα.........(iv)
and a = Rα
From Eqs. (ii) and (iv), we get
T3−T1=2Iαr=2IaR2
From Eqs. (i) and (iii), we get
(M−m)g=(M+m)a+T3−T1⇒(M−m)g=(M+m)a+2Iar2⇒a=(M−m)gM+m+2Ir2