Questions
Each pulley in the figure has radius r and moment of inertia I. The acceleration of the block is
detailed solution
Correct option is A
T1−mg=ma……..(i)rT2−T1=Iα.........(ii)Mg−T3=Ma.........(iii)rT3−T2=Iα.........(iv)and a = RαFrom Eqs. (ii) and (iv), we getT3−T1=2Iαr=2IaR2From Eqs. (i) and (iii), we get(M−m)g=(M+m)a+T3−T1⇒(M−m)g=(M+m)a+2Iar2⇒a=(M−m)gM+m+2Ir2Talk to our academic expert!
Similar Questions
A uniform rood AB of length and mass is free to rotate about point A. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is , the initial angular acceleration of the rod will be
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