Each pulley in the figure has radius r and moment of inertia I. The acceleration of the block is
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a
(M−m)gM+m+2Ir2
b
(M−m)gM+m−2Ir2
c
(M−m)gM+m+Ir2
d
(M−m)gM+m−Ir2
answer is A.
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Detailed Solution
T1−mg=ma……..(i)rT2−T1=Iα.........(ii)Mg−T3=Ma.........(iii)rT3−T2=Iα.........(iv)and a = RαFrom Eqs. (ii) and (iv), we getT3−T1=2Iαr=2IaR2From Eqs. (i) and (iii), we get(M−m)g=(M+m)a+T3−T1⇒(M−m)g=(M+m)a+2Iar2⇒a=(M−m)gM+m+2Ir2