First slide

potentiometer

Question

An Edison cell and a Iead accumulator when placed in series produce a null deflection at a distance 204 cm in a potentiometer. But when placed in opposition produces null deflection. at a distance of 36 cm. If the e.m.f. of Edison cell is 1 . 4 V, the e.m.f. of lead accumulator is

Moderate

A

2 V
B

14 V
C

20.4 V
D

(204 /36) V

Solution

$\frac{E_{1}}{E_{2}} = \frac{l_{1} + l_{2}}{l_{1} - l_{2}} or \frac{E_{1}}{1 \cdot 4} = \frac{204 + 36}{204 - 36} = 2 V$

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