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Q.

Effective capacitance of parallel combination of two capacitors C1  and C2  is 10μF. When these capacitors are individually connected to a voltage source of  1 V, the energy stored in the capacitor C2  is 4 times that of C1 . If these capacitors are connected in series, their effective capacitance will be:

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a

1.6μF

b

3.2μF

c

8.4μF

d

4.2μF

answer is A.

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Detailed Solution

Given : Capacitors connected in parallel :   C1+C2=10μF........(i)Now, they are connected individually to same voltage source. ∴4×Energy in C1 = Energy in C2 ⇒412C1V2=12C2V2    ⇒4C1=C2........iifrom equation (i) & (ii)  C1=2μF                    C2=8μF   If they are in series    Ceq.=C1C2C1+C2=2×82+8=1.6μF
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