Effective capacitance of parallel combination of two capacitors $$C1$$ and $$C2$$ is $$10$$μF. When these capacitors are individually connected to a voltage source of $$1$$ V, the energy stored in the capacitor $$C2$$ is $$4$$ times that of $$C1$$ . If these capacitors are connected in series, their effective capacitance will be:

Question

Effective capacitance of parallel combination of two capacitors $$C1$$  and $$C2$$  is $$10$$μF. When these capacitors are individually connected to a voltage source of  $$1$$ V, the energy stored in the capacitor $$C2$$  is $$4$$ times that of $$C1$$ . If these capacitors are connected in series, their effective capacitance will be:

Infinity Learn · Accepted Answer

Given : Capacitors connected in parallel :   $$C1+C2=10$$μF........(i)Now$$, they are connected individually to same voltage source. ∴$$4$$×Energy in $$C1$$ $$=$$ Energy in $$C2$$ ⇒$$412C1V2=12C2V2$$    ⇒$$4C1=C2$$........iifrom equation $$(i) & (ii)  $$C1=2$$μF                    $$C2=8$$μF   If they are in series    Ceq.$$=C1C2C1+C2=2$$×$$82+8=1.6$$μF

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