Questions
The efficiency of a Carnot cycle is . By lowering the temperature of sink by 65 K, it increases to . The initial and final temperatures of the sink are
a
390 K and 325 K
b
450 K and 410 K
c
350 K and 275 K
d
400 K and 310 K
detailed solution
Correct option is A
η = T1-T2T1= 16 --------(i) η' = T1-(T2-65)T1 = 13---------(ii)From equations (i) and (ii)η'η= (T1-T2+65T1)(T1T1-T2) = (13)(16) = 2or T1 -T2+ 65T1-T2 = 2or T1-T2= 65--------(iii)From equation (i), 65T1= 16 or T1 = 390 Kand from equation (iii), T2-T1 - 65 = 325 KTalk to our academic expert!
Similar Questions
For which combination of working temperatures of source and sink, the efficiency of Carnot's heat engine is maximum?
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions
