Questions
The efficiency of Carnot engine is 50% and temperature of sink is 500 K. If the temperature of source is kept constant and its efficiency is to be raised to 60% then the required temperature of sink will be
detailed solution
Correct option is C
1−T2T1=50100⇒T1=2T2=2×500k=1000k∴1−T211000=60100⇒T21=0.4×1000k=400KTalk to our academic expert!
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