The efficiency of a carnot engine is $$50$$% and temperature of sink is $$500$$ K. If temperature of source is kept constant and its efficiency raised to $$60$$%, then the required temperature of sink will be?

Question

Infinity Learn · Accepted Answer

efficiency of carnot engine is η$$=1-T2T1$$  here $$T1=temperature$$ of source, $$T2=Temperature$$ of $$sink=500K$$ $$(given)given$$ η$$=50$$%$$=50100$$  substitute given values in efficiency $$equation12=1$$−$$500T1$$    $$T1=1000$$ K       By the question   if η$$=60$$%$$=60100$$   η$$=1-T2T1$$   substitute the given values in the second part of question  $$60100=1-T21000T21000=1$$−$$610$$  $$T2=400$$ K  temperature of $$sink=400$$ K

The efficiency of a carnot engine is 50% and temperature of sink is 500 K. If temperature of source is kept constant and its efficiency raised to 60%, then the required temperature of sink will be?

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