The efficiency of a carnot engine is 50% and temperature of sink is 500 K. If temperature of source is kept constant and its efficiency raised to 60%, then the required temperature of sink will be?

efficiency of carnot engine is η=1-T2T1  here T1=temperature of source, T2=Temperature of sink=500K (given)given η=50%=50100  substitute given values in efficiency equation12=1−500T1    T1=1000 K       By the question   if η=60%=60100   η=1-T2T1   substitute the given values in the second part of question  60100=1-T21000T21000=1−610  T2=400 K  temperature of sink=400 K