Questions
Efficiency of a Carnot engine is 50% when temperature of outlet is 500 K. ln order to increase efficiency up to 60% keeping temperature of intake the same what is temperature of outlet?
detailed solution
Correct option is B
η = 1- T2T1 ⇒ 12=1-500T1 ⇒ 500T1 = 12-----(i) 60100 = 1-T2'T1 ⇒ T2'T1 = 25----------(ii)Dividing equation (i) by (ii), 500T2' = 54 ⇒ T2 = 400 KTalk to our academic expert!
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