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Q.

Efficiency of a Carnot engine is 50% when temperature of outlet is 500 K. ln order to increase efficiency up to 60% keeping temperature of intake the same what is temperature of outlet?

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a

200 K

b

400 K

c

600 K

d

800 K

answer is B.

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Detailed Solution

η = 1- T2T1  ⇒  12=1-500T1  ⇒ 500T1 = 12-----(i)       60100 = 1-T2'T1 ⇒ T2'T1 = 25----------(ii)Dividing equation (i) by (ii), 500T2' = 54  ⇒ T2 = 400 K
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