Efficiency of a Carnot engine is 50% when temperature of outlet is 500 K. In order to increase efficiency up to 60% keeping temperature of intake the same what is temperature of outlet
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a
200 K
b
400 K
c
600 K
d
800 K
answer is B.
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Detailed Solution
η=1−T2T1⇒12=1−500T1⇒500T1=12 ..........(i)60100=1−T2′T1⇒T2′T1=25 ........(ii)Dividing equation (i) by (ii), 500T2′=54⇒T2′=400K
Efficiency of a Carnot engine is 50% when temperature of outlet is 500 K. In order to increase efficiency up to 60% keeping temperature of intake the same what is temperature of outlet