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Q.

Efficiency of a Carnot engine is 50% when temperature of outlet is 500 K. In order to increase efficiency up to 60% keeping temperature of intake the same what is temperature of outlet

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a

200 K

b

400 K

c

600 K

d

800 K

answer is B.

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Detailed Solution

η=1−T2T1⇒12=1−500T1⇒500T1=12   ..........(i)60100=1−T2′T1⇒T2′T1=25   ........(ii)Dividing equation (i) by (ii),      500T2′=54⇒T2′=400K
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Efficiency of a Carnot engine is 50% when temperature of outlet is 500 K. In order to increase efficiency up to 60% keeping temperature of intake the same what is temperature of outlet