Questions
Efficiency of an engine working on Carnot cycle is 60%. If the temperature of sink is decreased by 25% and that of the source in increased by 25%, then new efficiency of the engine will be
detailed solution
Correct option is C
n=1−T2T1⇒0.6=1−T2T1⇒T2T1=0.4n1=1−T21T11=1−34T254T1=1−35.T2T1=(1−35×0.4)=76%Talk to our academic expert!
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For which combination of working temperatures of source and sink, the efficiency of Carnot's heat engine is maximum?
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