First slide

Capacitance

Question

Eight drops of mercury of equal radii possessing equal charges combine to form a big drop. Then the capacitance of bigger drop compared to each individual small drop is

Moderate

A

8 times
B

4 times
C

2 times
D

32 times

Solution

Volume of 8 small drops = Volume of big drop
$8 \times \frac{4}{3} {πr}^{3} = \frac{4}{3} {πR}^{3} \Rightarrow R = 2 r$
As capacity is proportional to r, hence capacity becomes 2 times.

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