Questions
Eight drops of mercury of equal radii possessing equal charges combine to form a big drop. Then the capacitance of bigger drop compared to each individual small drop is
detailed solution
Correct option is C
Volume of 8 small drops = Volume of big drop8×43πr3=43πR3⇒R=2rAs capacity is proportional to r, hence capacity becomes 2 times.Talk to our academic expert!
Similar Questions
Initial charge on conducting sphere of radius r is Q0. If S is closed at t = 0 then charge on the sphere at any time t is
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