First slide

Pontial due to

Question

Eight equal charged tiny drops are combined to form a big drop. If the potential on each drop is 10V. Then potential of big drop will be :

Moderate

A

40 V
B

10 V
C

30 V
D

20 V

Solution

Volume = constant $\Rightarrow 8 x \frac{4}{3} {πr}^{3} = \frac{4}{3} {πR}^{3}$
$\Rightarrow r = \frac{R}{2}$
$V_{big} = \frac{k (8 q)}{R} = \frac{8 kq}{2 r} = \frac{4 kq}{r} = 4 V_{tiny} = 4 x 10 V = 40 V$

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