Q.

Eight mercury droplets having a radius of 1 mm and a charge of 0.066 pC each merge to form one droplet. Its potential is

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a

0.297 V

b

1.2 V

c

3.6 V

d

2.376 V

answer is D.

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Detailed Solution

8×43πr3=43πR3  or  R=2mm So,     V=9×109×0.066×10−122×10−3               =2.376V
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