Q.
Eight mercury droplets having a radius of 1 mm and a charge of 0.066 pC each merge to form one droplet. Its potential is
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a
0.297 V
b
1.2 V
c
3.6 V
d
2.376 V
answer is D.
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Detailed Solution
8×43πr3=43πR3 or R=2mm So, V=9×109×0.066×10−122×10−3 =2.376V
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