First slide

Electrostatic potential

Question

Eight mercury droplets having a radius of 1 mm and a charge of 0.066 pC each merge to form one droplet. Its potential is

Moderate

A

0.297 V
B

1.2 V
C

3.6 V
D

2.376 V

Solution

$8 \times \frac{4}{3} π (r^{3}) = \frac{4}{3} {πR}^{3} or R = 2 mm So, V = \frac{(9 \times 10^{9}) \times (0 .066 \times 10^{- 12})}{(2 \times 10^{- 3})} = 2.376 V$

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