Questions
Eight mercury droplets having a radius of 1 mm and a charge of 0.066 pC each merge to form one droplet. Its potential is
detailed solution
Correct option is D
8×43πr3=43πR3 or R=2mm So, V=9×109×0.066×10−122×10−3 =2.376VTalk to our academic expert!
Similar Questions
Two parallel plates separated by a distance of 5 mm are kept at a potential difference of 50 V. A particle of mass 10-15 kg and charge 10-11 C enters in it with a velocity 107 m/s. The acceleration of the particle will be
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