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Q.

An elastic spring of unstretched length L and force constant K is stretched by amount x. It is further stretched by another length y. The work done in the second stretching is

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a

12Ky2

b

12K(x2+y2)

c

12K(x+y)2

d

12Ky(2x+y)

answer is D.

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Detailed Solution

Work done to stretch to length x = 12KX2 = W1Work done to stretch to length y = 12K(X+Y)2 =W2W = W2- W1W = 12k(y+x)2-x2)
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