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Q.

An elastic string of unstretched length l and force constant k is stretched by a small length x. It is further stretched by another small length y. The work done in the second stretching is :

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a

12kx2

b

12kx2+y2

c

12ky(2x+y)

d

12kx(x+2y)

answer is C.

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Detailed Solution

Initial spring potential energy= 12kx2Final spring potential energy= 12kx+y2Hence work done= 12k[x+y2-x2]

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An elastic string of unstretched length l and force constant k is stretched by a small length x. It is further stretched by another small length y. The work done in the second stretching is :