An electric bulb is designed to draw P_o power at V_o voltage, If the voltage is V, it draws P power. Then

• A

  $\mathrm{P}=\frac{{\mathrm{V}}_0}{\mathrm{V}}{\mathrm{P}}_0$

• B

  $\mathrm{P}={\left(\frac{\mathrm{V}}{{\mathrm{V}}_0}\right)}^2{\mathrm{P}}_0$

• C

  $\mathrm{P}={\left(\frac{{\mathrm{V}}_0}{\mathrm{V}}\right)}^2{\mathrm{P}}_0$

• D

  $\mathrm{P}=\frac{\mathrm{V}}{{\mathrm{V}}_0}\mathrm{P}$