Questions
An electric bulb rated for 500 watts at 100 volts is used in a circuit having a 200 volt supply. The resistance R that must be put in series with the bulb so that the bulb draws 500 W is
detailed solution
Correct option is B
Rated current through the circuit, i=500100=5APotential difference across R, 100=5 × R⇒ R=20 ΩTalk to our academic expert!
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A resistor R is connected across a battery of emf 12 V. It observed that terminal potential differenceis 9 V and the power delivered to resistor is 18 W. Internal resistance of the battery ‘r’ and the resistance R are respectively
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