Q.
An electric dipole is along a uniform electric field. If it is deflected by 600 , work done by an agent is 2×10−19J . Then the extra work done by an agent if it is deflected by 30º further is
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a
2.5×10−19J
b
2×10−19J
c
4×10−19J
d
2×10−16J
answer is B.
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Detailed Solution
W1=pE(1−cosθ) 2×10-19=pE(1−cos60) pE=4×10-19---(1) and W2=pE(cosθ1−cosθ2) =4×10-19cos60-cos90=2×10-19J
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