Question

An electric dipole, consisting of two opposite charges of 2 x 10^-6 C each separated by a distance of 3 cm is placed in an electric field of 2 x 10⁵ newton per coulomb. The maximum torque on the dipole will be

Easy

Solution

$τ = p \times E Maximum torque τ = pE Here p = (2 \times 10^{- 6} C) \times (0 .03 m) = 6 \times 10^{- 8} Cm ∴ Maximum torque = (6 \times 10^{- 8}) (2 \times 10^{5}) = 12 \times 10^{- 3} Nm$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

SCAN ME