Download the app

Questions  

Electric dipole consists of two charges of magnitude 0.1μC separated by a distance of 2 cm. The dipole is in an external field of 105 N/C. What maximum torque does the field exert on the dipole?

a
10−4N−m
b
2×10−8N−m
c
2×10−4N−m
d
3×10−4N−m

detailed solution

Correct option is C

qc=0.1μC=10−7C,2a=2cm=2×10−2mE=105N/C,τ=?As we know τ=P×Esin⁡θ, For maxτ,sin⁡θ=1τ=2×10−4N−m ∵sin⁡θmax=1

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Two opposite and equal charges 4 × 10–8 coulomb when placed 2 × 10–2 cm away, from a dipole. If this dipole is placed in an external electric field 4 × 108 newton/coulomb, the value of maximum torque and the work done in rotating it through 180o will be


phone icon
whats app icon