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An electric dipole consists of two opposite charges of magnitude q=1 × 10−6 C separated by 2.0 cm. The dipole is placed in an external field of 1 × 105 NC−1. What maximum torque does the field exert on the dipole? How much work must an external agent do to turn the dipole end for end, starting from position of alignment θ=00

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a

4.4 × 106 N−m, 3.2 × 10−4 J

b

− 2 × 103N−m,−4 × 103J

c

4 × 103 N−m, 2 × 10−3

d

2 × 10−3 N−m, 4 × 10−3J

answer is D.

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Detailed Solution

q=±1 × 10−6C,2 a=2.0 cm =2.0 × 10−2mE=1 × 105 NC−1 θ1=0∘,θ2=180∘. τmax=pE=q(2a)E =1 × 10−6× 2.0 × 10−2× 1 ×105 =2 × 10−3 N.m. W=pE(cos θ1−cos θ2) =(10−6× 2 × 10−2) (105)(cos 0∘−cos 180∘) W=4 × 10−3 J.

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An electric dipole consists of two opposite charges of magnitude q=1 × 10−6 C separated by 2.0 cm. The dipole is placed in an external field of 1 × 105 NC−1. What maximum torque does the field exert on the dipole? How much work must an external agent do to turn the dipole end for end, starting from position of alignment θ=00