An electric dipole made up of a positive and negative charge, each of 1μC separated by a distance of 2cm is placed in an electric field of 105N/C , then the work done in rotating the dipole from the position of stable equilibrium through an angle of 1800 is

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2×10−3Joule

2×10−8Joule

4×10−3Joule

Zero

answer is C.

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Detailed Solution

w=2pE = 2×1×10−6×2×10−2×105=4×10−3J

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