An electric dipole of moment p→=−i^−3j^+2k^×10−29Cm is at the origin 0,0,0 . The electric field due to the dipole at r→=+i^+3j^+5k^ (note that r→.p→=0 ) is parallel to:
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a
+i^−3j^−2k^
b
−i^−3j^+2k^
c
−i^+3j^−2k^
d
+i^+3j^−2k^
answer is D.
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Detailed Solution
r→.p→=+i^+3j^+5k^.−i^−3j^+2k^×10−29=0 So , r→ and p→ are perpendicular to each other.Hence, the point is on perpendicular besector of dipole, where E→ is anti parallel to P→.∴E→ is along +i^+3j^−2k^
An electric dipole of moment p→=−i^−3j^+2k^×10−29Cm is at the origin 0,0,0 . The electric field due to the dipole at r→=+i^+3j^+5k^ (note that r→.p→=0 ) is parallel to: