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Q.

An electric dipole of moment  p→=−i^−3j^+2k^×10−29Cm is at the origin 0,0,0 . The electric field due to the dipole at r→=+i^+3j^+5k^ (note  that  r→.p→=0 ) is parallel to:

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a

+i^−3j^−2k^

b

−i^−3j^+2k^

c

−i^+3j^−2k^

d

+i^+3j^−2k^

answer is D.

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Detailed Solution

r→.p→=+i^+3j^+5k^.−i^−3j^+2k^×10−29=0 ​So , r→ and p→ are perpendicular to each other.Hence, the point is on perpendicular besector of dipole, where E→ is anti parallel to P→.​∴E→ is along +i^+3j^−2k^
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