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Q.

A electric dipole is placed at an angle of 300 with an electric field intensity 2×105N C−1 . It experiences a torque equal to 8 N m . The charge on the dipole, if the dipole length is 2 cm , is

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a

8 mc

b

4 mc

c

5 mc

d

7 μC

answer is B.

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Detailed Solution

Here, θ=30º,E=2×105NC−1 τ=8Nm,l=2cm=0.02m,q=?τ=PEsinθ=(ql)Esinθ∴q=τElsinθ=82×105×0.02×12=82×103=4×10−3C=4mC .

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