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Q.

An electric dipole is placed at an angle of 300with an electric field of intensity 2×105NC−1, It experiences torque of 4Nm. Calculate the charge on the dipole if the dipole length is 2cm.

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a

8 mC

b

4 mC

c

8 μC

d

2 mC

answer is D.

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Detailed Solution

Torque, τ→=p→×E→=pEsinθ4=p×2×105×sin300Or, p=42×105×sin300=4×10−5CmDipole moment, p=q×lq=pl=4×10−50.02=2×10−3C=2mC

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An electric dipole is placed at an angle of 300with an electric field of intensity 2×105NC−1, It experiences torque of 4Nm. Calculate the charge on the dipole if the dipole length is 2cm.