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Q.

An electric dipole is placed at an angle of 60∘  with an electric filed of intensity 105 NC−1.  It experiences a torque equal to 83  Nm. Calculate the charge placed at 2 cm.

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a

−8  ×  103C

b

8.54  ×  10−4 C

c

8  ×  10−3 C

d

0.85  ×  10−6 C

answer is C.

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Detailed Solution

Here, θ=60∘, E=105 NC−1 τ=83 Nm, q=?,  2a=2 cm=2 × 10−2mFrom τ=pE sin θ=q(2a) E sin θq=τ2 a E sin θ=832  ×  10−2×105×sin 60∘    =832 × 103×3/2q=8  ×  10−3 C
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