First slide

Electric dipole

Question

An electric dipole is placed in a uniform electric field. Torque experienced by the dipole is 8 x 10^-6 N-m and the magnitude of potential energy stored in the system is $\frac{8}{\sqrt{3}}$ µJ. Then the angle between the dipole moment vector and the electric field vector is

Moderate

A

45°
B

90°
C

60°
D

30°

Solution

$τ = = pEsinθ |U| = pEcosθ ∴ tanθ = \frac{τ}{|U|} = \frac{8 \times 10^{- 6}}{(\frac{8}{\sqrt{3}} \times 10^{- 6})} = \sqrt{3} \Rightarrow 60^{o}$

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