An electric field is acting vertically upwards. A small body of mass $$1$$ gm and charge $$-1$$μC is projected with a velocity $$10$$ $$m/s$$ at an angle $$450$$ with horizontal. Its horizontal range is $$2m$$ then the intensity of electric field is : (g$$ $$=$$ $$10$$ $$m/s2)

Question

An electric field is acting vertically upwards. A small body of mass $$1$$ gm and charge  $$-1$$μC  is projected with a velocity $$10$$ $$m/s$$ at an angle $$450$$ with horizontal. Its horizontal range is $$2m$$ then the intensity of electric field is : (g$$ $$=$$ $$10$$ $$m/s2)

Infinity Learn · Accepted Answer

As charge is negative and the electric field is vertically upwards the total force acting on the charge is vertically downwards.  Hence the net acceleration downwards is $$g+qEmR=V2sin2$$θ$$g+qEm=V2g+qEm$$θ$$=45oR=10010+10$$−$$6E10$$−$$3=10+10$$−$$3E=50E=40$$×$$103$$  $$N/C$$

An electric field is acting vertically upwards. A small body of mass 1 gm and charge - $1 μ C$ is projected with a velocity 10 m/s at an angle $45^{0}$ with horizontal. Its horizontal range is 2m then the intensity of electric field is : (g = 10 $m / s^{2}$ )

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An electric field is acting vertically upwards. A small body of mass 1 gm and charge -1μC is projected with a velocity 10 m/s at an angle 450 with horizontal. Its horizontal range is 2m then the intensity of electric field is : (g = 10 m/s2)

Unlock the full solution & master the concept.

Ready to Test Your Skills?

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An electric field is acting vertically upwards. A small body of mass 1 gm and charge - $1 μ C$ is projected with a velocity 10 m/s at an angle $45^{0}$ with horizontal. Its horizontal range is 2m then the intensity of electric field is : (g = 10 $m / s^{2}$ )