Q.
The electric field associated with an EM wave in vacuum is given by E→=40cos kz-6 x 108ti^, where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is
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a
2 m–1
b
0.5 m–1
c
6 m–1
d
3 m–1
answer is A.
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Detailed Solution
K=2πλ=2πCn=2πnC=ωC=6 x 1083 x 108=2 m-1
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