Q.

The electric field associated with an EM wave in vacuum is given by E→=40cos kz-6 x 108ti^, where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is

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a

2 m–1

b

0.5 m–1

c

6 m–1

d

3 m–1

answer is A.

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Detailed Solution

K=2πλ=2πCn=2πnC=ωC=6 x 1083 x 108=2 m-1
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