First slide

Nature of electromagnetic wave

Question

The electric field associated with an EM wave in vacuum is given by $\vec{E} = 40 \cos (kz - 6 x 10^{8} t) \hat{i}$ , where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is

Moderate

A

2 m^–1
B

0.5 m^–1
C

6 m^–1
D

3 m^–1

Solution

$K = \frac{2 π}{λ} = \frac{2 π}{(\frac{C}{n})} = \frac{2 πn}{C} = \frac{ω}{C} = \frac{6 x 10^{8}}{3 x 10^{8}} = 2 m^{- 1}$

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