First slide

Photoelectric effect and study of photoelectric effect

Question

The electric field associated with a light wave is given by $E = E_{0} \sin [(1.57 \times 10^{7} m^{- 1}) (x - c t)]$ . Find the stopping potential (in eV) when this light is used in an experiment on photoelectric effect with a metal having work-function 1.9 eV.

Moderate

Solution

$\begin{array}{l} F r e q u e n c y, f = \frac{ω}{2 π} = \frac{(1.57 \times 10^{7}) c}{2 π} H z \\ E n e r g y, E = h f J = \frac{h f}{1.6 \times 10^{- 19}} e V = \frac{(6.63 \times 10^{- 34}) (1.57 \times 10^{7}) (3 \times 10^{8})}{1.6 \times 10^{- 19} \times 2 \times π} e V = 3.1 e V \\ ∴ K_{\max} = E - ϕ = 3.2 - 1.9 = 1.2 e V \end{array}$

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