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The electric field in a certain region is given by E→=(5i^-3j^)kV/m. The potential difference VB-VA between points A and B, having coordinates (4,0,3)m and (10,3,0)m respectively, is equal to

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a

21kV

b

-21kV

c

39kV

d

-39kV

answer is B.

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Detailed Solution

Here, E→=(5i^−3j^ )kV/mVB−VA=−∫rArBE→·dr→⇒VB−VA=−∫(4,0,3)(10,3,0)(5i^−3j^)·(dxi^+dyj^+dzk^)⇒VB−VA=−∫4105dx + ∫033dy+0=−5[x]+3[y]⇒VB−VA=−5(10−4)+3(3−0)=−30+9=−21kV

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