Q.

The electric field due to a charge at a distance of 3 m from it is 500 N/coulomb. The magnitude of the charge is 14πε0=9×109N−m2coulomb2

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a

2.5 micro-coulomb

b

2.0 micro-coulomb

c

1.0 micro-coulomb

d

0.5 micro-coulomb

answer is D.

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Detailed Solution

E=9×109×Qr2⇒500=9×109×Q(3)2⇒Q=0.5μC
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