First slide
Finding field strength using Gauss's Law
Question

The electric field due to a uniformly charged sphere of radius R as a function of the distance from its centre is represented graphically by

Moderate
Solution

Einside =ρ3ε0r                     (r<R) Eoutside =ρR33ε0r2                  (rR)

i.e. inside the uniformly charged sphere field varies linearly (E  r) with distance and outside varies

according to E1r2

Aliter: Outside the spherical charge, the intensity of electric field at a distance r from the centre of the charge

 E=14πε0qr2                    (if r>R)

On the surface of spherical charge, E=14πε0-qr2

and inside the spherical surface the electric field

E=14πε0qrR3                      ( if r<R)

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