Q.

An electric field E→=4xi^−y2+1j^N/C passes through the box shown in figure. The flux of the electric field through surfaces ABCD and BCGF are marked as ϕ1  and  ϕ2 respectively .The difference between ϕ1−ϕ2 is in Nm2/C ____

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answer is -0048.00.

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Detailed Solution

E¯=4xi^−y2+1j^.N/cArea of ABCD is dsABCD=lb k^    =3×2k^   =6k^    ϕ1=E¯.ds¯ABCD  =0Area of BCGF dsBCGF=lb i^   =2×2i^   =4i^   ϕ2=E¯.ds¯BCGF  =43i^−y2+1j^.4i^     ϕ2=12×4  =48Nm2/C   ⇒ϕ1−ϕ2=−48.00Nm2/C
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