The electric field of an electromagnetic wave in free space is given by E→=10 cos107t+kxj^ V/m, where t and x are in seconds and metres respectively. It can be inferred that1) the wavelength λ is 188.4 m2) the wave number k is 0.33 rad/m.3) the wave amplitude is 10 V/m.4) the wave is propagating along + x direction.Which one of the following pairs of statements is correct ?
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
(3) and (4)
b
(1) and (2)
c
(2) and (3)
d
(1) and (3)
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Wavelength λ ; Given ω = 107 rad / secλ=Cn=3 x 108ω2π=3 x 1081072π=30 x 2π=188.4 mAmplitude of electric field = 10 V/m