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Q.

The electric field on an electromagnetic wave is given by E=(50N/C)sin⁡ωt−xc The energy contained in a cylinder of cross-section 10 cm2 and length 50 cm along the x-axis will be

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a

5⋅5×10−9J

b

5⋅54×10−10J

c

5⋅5×10−12J

d

5⋅5×10−15J

answer is C.

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Detailed Solution

The average average density is given byuav=12ϵ0E02Total volume of cylinderV=Al Total energy contained in the cylinderU=uav(V)=12∈0E02×Al =12×8.86×10−12×(50)2 ×10×10−4×50×10−2J =5⋅5×10−12J
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The electric field on an electromagnetic wave is given by E=(50N/C)sin⁡ωt−xc The energy contained in a cylinder of cross-section 10 cm2 and length 50 cm along the x-axis will be