The electric field on an electromagnetic wave is given by E=(50N/C)sinωt−xc The energy contained in a cylinder of cross-section 10 cm2 and length 50 cm along the x-axis will be
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a
5⋅5×10−9J
b
5⋅54×10−10J
c
5⋅5×10−12J
d
5⋅5×10−15J
answer is C.
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Detailed Solution
The average average density is given byuav=12ϵ0E02Total volume of cylinderV=Al Total energy contained in the cylinderU=uav(V)=12∈0E02×Al =12×8.86×10−12×(50)2 ×10×10−4×50×10−2J =5⋅5×10−12J
The electric field on an electromagnetic wave is given by E=(50N/C)sinωt−xc The energy contained in a cylinder of cross-section 10 cm2 and length 50 cm along the x-axis will be